2x+3(x-5)-(10-x)-3=2

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Solution for 2x+3(x-5)-(10-x)-3=2 equation: 



2x+3(x-5)-(10-x)-3=2

We move all terms to the left:

2x+3(x-5)-(10-x)-3-(2)=0

We add all the numbers together, and all the variables

2x+3(x-5)-(-1x+10)-3-2=0

We add all the numbers together, and all the variables

2x+3(x-5)-(-1x+10)-5=0

We multiply parentheses

2x+3x-(-1x+10)-15-5=0

We get rid of parentheses

2x+3x+1x-10-15-5=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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