2x+3+2=(x+1)-3(1-x)

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Solution for 2x+3+2=(x+1)-3(1-x) equation: 



2x+3+2=(x+1)-3(1-x)

We move all terms to the left:

2x+3+2-((x+1)-3(1-x))=0

We add all the numbers together, and all the variables

2x-((x+1)-3(-1x+1))+3+2=0

We add all the numbers together, and all the variables

2x-((x+1)-3(-1x+1))+5=0



We calculate terms in parentheses: -((x+1)-3(-1x+1)), so:

(x+1)-3(-1x+1)

We multiply parentheses

(x+1)+3x-3

We get rid of parentheses

x+3x+1-3

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

2x-4x+2+5=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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