2x+3+4x=3(2x-4)+x

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Solution for 2x+3+4x=3(2x-4)+x equation: 



2x+3+4x=3(2x-4)+x

We move all terms to the left:

2x+3+4x-(3(2x-4)+x)=0

We add all the numbers together, and all the variables

6x-(3(2x-4)+x)+3=0



We calculate terms in parentheses: -(3(2x-4)+x), so:

3(2x-4)+x

We add all the numbers together, and all the variables

x+3(2x-4)

We multiply parentheses

x+6x-12

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We get rid of parentheses

6x-7x+12+3=0

We add all the numbers together, and all the variables

-1x+15=0

We move all terms containing x to the left, all other terms to the right

-x=-15

x=-15/-1

x=+15

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