2x+3-(1x+3)=3x+2-(2x+2)

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Solution for 2x+3-(1x+3)=3x+2-(2x+2) equation: 



2x+3-(1x+3)=3x+2-(2x+2)

We move all terms to the left:

2x+3-(1x+3)-(3x+2-(2x+2))=0

We add all the numbers together, and all the variables

2x-(x+3)-(3x+2-(2x+2))+3=0

We get rid of parentheses

2x-x-(3x+2-(2x+2))-3+3=0



We calculate terms in parentheses: -(3x+2-(2x+2)), so:

3x+2-(2x+2)

determiningTheFunctionDomain
3x-(2x+2)+2

We get rid of parentheses

3x-2x-2+2

We add all the numbers together, and all the variables

x

Back to the equation:

-(x)



We add all the numbers together, and all the variables

=0

x=0/1

x=0

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