2x+3-(x-2)+4x=3x+2(x-5)

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Solution for 2x+3-(x-2)+4x=3x+2(x-5) equation: 



2x+3-(x-2)+4x=3x+2(x-5)

We move all terms to the left:

2x+3-(x-2)+4x-(3x+2(x-5))=0

We add all the numbers together, and all the variables

6x-(x-2)-(3x+2(x-5))+3=0

We get rid of parentheses

6x-x-(3x+2(x-5))+2+3=0



We calculate terms in parentheses: -(3x+2(x-5)), so:

3x+2(x-5)

We multiply parentheses

3x+2x-10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

5x-(5x-10)+5=0

We get rid of parentheses

5x-5x+10+5=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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