2x+3-2*(x-1)=-2*(x-3)+1

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Solution for 2x+3-2*(x-1)=-2*(x-3)+1 equation: 



2x+3-2(x-1)=-2(x-3)+1

We move all terms to the left:

2x+3-2(x-1)-(-2(x-3)+1)=0

We multiply parentheses

2x-2x-(-2(x-3)+1)+2+3=0



We calculate terms in parentheses: -(-2(x-3)+1), so:

-2(x-3)+1

We multiply parentheses

-2x+6+1

We add all the numbers together, and all the variables

-2x+7

Back to the equation:

-(-2x+7)



We add all the numbers together, and all the variables

-(-2x+7)+5=0

We get rid of parentheses

2x-7+5=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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