2x+3-5x=6+2(4-x)

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Solution for 2x+3-5x=6+2(4-x) equation: 



2x+3-5x=6+2(4-x)

We move all terms to the left:

2x+3-5x-(6+2(4-x))=0

We add all the numbers together, and all the variables

2x-5x-(6+2(-1x+4))+3=0

We add all the numbers together, and all the variables

-3x-(6+2(-1x+4))+3=0



We calculate terms in parentheses: -(6+2(-1x+4)), so:

6+2(-1x+4)

determiningTheFunctionDomain
2(-1x+4)+6

We multiply parentheses

-2x+8+6

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We get rid of parentheses

-3x+2x-14+3=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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