2x+3/3x=7/3-4/x

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Solution for 2x+3/3x=7/3-4/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+(3/3)*x = 7/3-(4/x) // - 7/3-(4/x)

2*x+(3/3)*x+4/x-(7/3) = 0

2*x+(3/3)*x+4/x-7/3 = 0

3*x^1+4*x^-1-7/3*x^0 = 0

(3*x^2-7/3*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-7/3*x^1+4*x^0) = 0

x^1

3*x^2+(-7/3)*x+4 = 0

3*x^2+(-7/3)*x+4 = 0

DELTA = (-7/3)^2-(3*4*4)

DELTA = -383/9

DELTA < 0

x in { } 

x belongs to the empty set

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