2x+3/3x=x/2x-3

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Solution for 2x+3/3x=x/2x-3 equation:



2x+3/3x=x/2x-3
We move all terms to the left:
2x+3/3x-(x/2x-3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x-3)!=0
x∈R
We get rid of parentheses
2x+3/3x-x/2x+3=0
We calculate fractions
(-3x^2)/6x^2+2x+6x/6x^2+3=0
We multiply all the terms by the denominator
(-3x^2)+2x*6x^2+6x+3*6x^2=0
We add all the numbers together, and all the variables
(-3x^2)+6x+2x*6x^2+3*6x^2=0
Wy multiply elements
(-3x^2)+12x^3+18x^2+6x=0
We get rid of parentheses
-3x^2+12x^3+18x^2+6x=0
We do not support expression: x^3

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