2x+3/4(4c+16)=7

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Solution for 2x+3/4(4c+16)=7 equation: 


x in (-oo:+oo)

(3/4)*(4*c+16)+2*x = 7 // - 7

(3/4)*(4*c+16)+2*x-7 = 0

3/4*(4*c+16)+2*x-7 = 0

3/4*(4*c+16)+2*x-7 = 0

3*c+2*x-7+12 = 0

3*c+2*x+5 = 0

3*c+2*x+5 = 0

3*c+2*x+5 = 0 // - 3*c+5

2*x = -(3*c+5) // : 2

x = (-(3*c+5))/2

x = (-(3*c+5))/2

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