2x+3/4(4x+16=7

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Solution for 2x+3/4(4x+16=7 equation: 



2x+3/4(4x+16=7

We move all terms to the left:

2x+3/4(4x+16-(7)=0



Domain of the equation: 4(4x+16-7!=0

x∈R



We multiply all the terms by the denominator


2x*4(4x+16-7+3=0

Wy multiply elements

8x^2(4=0

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