2x+3/5(4x+16)=7

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Solution for 2x+3/5(4x+16)=7 equation: 



2x+3/5(4x+16)=7

We move all terms to the left:

2x+3/5(4x+16)-(7)=0



Domain of the equation: 5(4x+16)!=0

x∈R



We multiply all the terms by the denominator


2x*5(4x+16)-7*5(4x+16)+3=0

Wy multiply elements

10x^2(4-35x(4+3=0

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