2x+3/5x=3

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Solution for 2x+3/5x=3 equation:



2x+3/5x=3
We move all terms to the left:
2x+3/5x-(3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We multiply all the terms by the denominator
2x*5x-3*5x+3=0
Wy multiply elements
10x^2-15x+3=0
a = 10; b = -15; c = +3;
Δ = b2-4ac
Δ = -152-4·10·3
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{105}}{2*10}=\frac{15-\sqrt{105}}{20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{105}}{2*10}=\frac{15+\sqrt{105}}{20} $

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