2x+32=(2/9)x

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Solution for 2x+32=(2/9)x equation:



2x+32=(2/9)x
We move all terms to the left:
2x+32-((2/9)x)=0
Domain of the equation: 9)x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
2x-((+2/9)x)+32=0
We multiply all the terms by the denominator
2x*9)x)-((+32*9)x)+2=0
We add all the numbers together, and all the variables
2x*9)x)-(288x)+2=0
We add all the numbers together, and all the variables
2x*9)x)-288x+2=0
Wy multiply elements
18x^2=0
a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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