2x+32=(2/9)x

Solution for 2x+32=(2/9)x equation:

2x+32=(2/9)x

We move all terms to the left:

2x+32-((2/9)x)=0


Domain of the equation: 9)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x-((+2/9)x)+32=0

We multiply all the terms by the denominator


2x*9)x)-((+32*9)x)+2=0

We add all the numbers together, and all the variables

2x*9)x)-(288x)+2=0

We add all the numbers together, and all the variables

2x*9)x)-288x+2=0

Wy multiply elements

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$