2x+32=-6(3x-2)

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Solution for 2x+32=-6(3x-2) equation: 



2x+32=-6(3x-2)

We move all terms to the left:

2x+32-(-6(3x-2))=0



We calculate terms in parentheses: -(-6(3x-2)), so:

-6(3x-2)

We multiply parentheses

-18x+12

Back to the equation:

-(-18x+12)



We get rid of parentheses

2x+18x-12+32=0

We add all the numbers together, and all the variables

20x+20=0

We move all terms containing x to the left, all other terms to the right

20x=-20

x=-20/20

x=-1

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