2x+34=4(x+5)e

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Solution for 2x+34=4(x+5)e equation:


Simplifying
2x + 34 = 4(x + 5) * e

Reorder the terms:
34 + 2x = 4(x + 5) * e

Reorder the terms:
34 + 2x = 4(5 + x) * e

Reorder the terms for easier multiplication:
34 + 2x = 4e(5 + x)
34 + 2x = (5 * 4e + x * 4e)
34 + 2x = (20e + 4ex)

Solving
34 + 2x = 20e + 4ex

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4ex' to each side of the equation.
34 + -4ex + 2x = 20e + 4ex + -4ex

Combine like terms: 4ex + -4ex = 0
34 + -4ex + 2x = 20e + 0
34 + -4ex + 2x = 20e

Add '-34' to each side of the equation.
34 + -4ex + -34 + 2x = -34 + 20e

Reorder the terms:
34 + -34 + -4ex + 2x = -34 + 20e

Combine like terms: 34 + -34 = 0
0 + -4ex + 2x = -34 + 20e
-4ex + 2x = -34 + 20e

Reorder the terms:
34 + -20e + -4ex + 2x = -34 + 20e + 34 + -20e

Reorder the terms:
34 + -20e + -4ex + 2x = -34 + 34 + 20e + -20e

Combine like terms: -34 + 34 = 0
34 + -20e + -4ex + 2x = 0 + 20e + -20e
34 + -20e + -4ex + 2x = 20e + -20e

Combine like terms: 20e + -20e = 0
34 + -20e + -4ex + 2x = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(17 + -10e + -2ex + x) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(17 + -10e + -2ex + x)' equal to zero and attempt to solve: Simplifying 17 + -10e + -2ex + x = 0 Solving 17 + -10e + -2ex + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-17' to each side of the equation. 17 + -10e + -2ex + -17 + x = 0 + -17 Reorder the terms: 17 + -17 + -10e + -2ex + x = 0 + -17 Combine like terms: 17 + -17 = 0 0 + -10e + -2ex + x = 0 + -17 -10e + -2ex + x = 0 + -17 Combine like terms: 0 + -17 = -17 -10e + -2ex + x = -17 Add '10e' to each side of the equation. -10e + -2ex + 10e + x = -17 + 10e Reorder the terms: -10e + 10e + -2ex + x = -17 + 10e Combine like terms: -10e + 10e = 0 0 + -2ex + x = -17 + 10e -2ex + x = -17 + 10e The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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