2x+3=3(x-2)2

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Solution for 2x+3=3(x-2)2 equation: 



2x+3=3(x-2)2

We move all terms to the left:

2x+3-(3(x-2)2)=0



We calculate terms in parentheses: -(3(x-2)2), so:

3(x-2)2

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

2x-6x+12+3=0

We add all the numbers together, and all the variables

-4x+15=0

We move all terms containing x to the left, all other terms to the right

-4x=-15

x=-15/-4

x=3+3/4

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