2x+3=6/5x+2.8

Solution for 2x+3=6/5x+2.8 equation:

2x+3=6/5x+2.8

We move all terms to the left:

2x+3-(6/5x+2.8)=0


Domain of the equation: 5x+2.8)!=0

x∈R


We get rid of parentheses

2x-6/5x-2.8+3=0

We multiply all the terms by the denominator


2x*5x-(2.8)*5x+3*5x-6=0

We multiply parentheses

2x*5x-14x+3*5x-6=0

Wy multiply elements

10x^2-14x+15x-6=0

We add all the numbers together, and all the variables

10x^2+x-6=0

a = 10; b = 1; c = -6;
Δ = b2-4ac
Δ = 12-4·10·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*10}=\frac{-1-\sqrt{241}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*10}=\frac{-1+\sqrt{241}}{20}
$