2x+3x+20=100-5x

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Solution for 2x+3x+20=100-5x equation: 



2x+3x+20=100-5x

We move all terms to the left:

2x+3x+20-(100-5x)=0

We add all the numbers together, and all the variables

2x+3x-(-5x+100)+20=0

We add all the numbers together, and all the variables

5x-(-5x+100)+20=0

We get rid of parentheses

5x+5x-100+20=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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