2x+3x+4x+6x+7x2=78

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Solution for 2x+3x+4x+6x+7x2=78 equation:



2x+3x+4x+6x+7x^2=78
We move all terms to the left:
2x+3x+4x+6x+7x^2-(78)=0
We add all the numbers together, and all the variables
7x^2+15x-78=0
a = 7; b = 15; c = -78;
Δ = b2-4ac
Δ = 152-4·7·(-78)
Δ = 2409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2409}}{2*7}=\frac{-15-\sqrt{2409}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2409}}{2*7}=\frac{-15+\sqrt{2409}}{14} $

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