2x+3x-20=32+x

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Solution for 2x+3x-20=32+x equation: 



2x+3x-20=32+x

We move all terms to the left:

2x+3x-20-(32+x)=0

We add all the numbers together, and all the variables

2x+3x-(x+32)-20=0

We add all the numbers together, and all the variables

5x-(x+32)-20=0

We get rid of parentheses

5x-x-32-20=0

We add all the numbers together, and all the variables

4x-52=0

We move all terms containing x to the left, all other terms to the right

4x=52

x=52/4

x=13

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