2x+3x-4-x=40+3-x

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Solution for 2x+3x-4-x=40+3-x equation: 



2x+3x-4-x=40+3-x

We move all terms to the left:

2x+3x-4-x-(40+3-x)=0

We add all the numbers together, and all the variables

2x+3x-x-(-1x+43)-4=0

We add all the numbers together, and all the variables

4x-(-1x+43)-4=0

We get rid of parentheses

4x+1x-43-4=0

We add all the numbers together, and all the variables

5x-47=0

We move all terms containing x to the left, all other terms to the right

5x=47

x=47/5

x=9+2/5

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