2x+3x-4=7(x+1)-5

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Solution for 2x+3x-4=7(x+1)-5 equation: 



2x+3x-4=7(x+1)-5

We move all terms to the left:

2x+3x-4-(7(x+1)-5)=0

We add all the numbers together, and all the variables

5x-(7(x+1)-5)-4=0



We calculate terms in parentheses: -(7(x+1)-5), so:

7(x+1)-5

We multiply parentheses

7x+7-5

We add all the numbers together, and all the variables

7x+2

Back to the equation:

-(7x+2)



We get rid of parentheses

5x-7x-2-4=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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