2x+3y=10;4x+12y=40

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Remember to put linear equations with variables x and y.
for example:
2x+y=8
x+3y=14

Solution for 2x+3y=10;4x+12y=40 system of equations: 


  • /| 2*x+3*y-10 = 0| 4*x+12*y-40 = 0
  • We try to solve the equation: 2*x+3*y-10 = 0
  • 2*x+3*y-10 = 0 // - 2*x-10
  • 3*y = -(2*x-10) // : 3
  • y = (-(2*x-10))/3
  • y = (10-(2*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 12*((10-(2*x))/3)+4*x-40 = 0| y = (10-(2*x))/3
  • (12*(10-2*x))/3+4*x-40 = 0
  • 40-4*x-40 = 0
  • -4*x = 0
  • -4*x = 0 // : -4
  • x = 0
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (10-(2*x))/3: 
  • y = (10-(0*2))/3
  • y = (0+10)/3
  • y = 10/3
  • We get a system of equations:
  • /| y = 10/3| x = 0

 

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