2x+3y=7;3x-3y=18

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Solution for 2x+3y=7;3x-3y=18 system of equations: 


  • /| 2*x+3*y-7 = 0| 3*x-(3*y)-18 = 0
  • We try to solve the equation: 2*x+3*y-7 = 0
  • 2*x+3*y-7 = 0 // - 2*x-7
  • 3*y = -(2*x-7) // : 3
  • y = (-(2*x-7))/3
  • y = (7-(2*x))/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 3*x-(3*((7-(2*x))/3))-18 = 0| y = (7-(2*x))/3
  • (-1*3*(7-2*x))/3+3*x-18 = 0
  • 5*x-18-7 = 0
  • 5*x-25 = 0
  • 5*x-25 = 0 // + 25
  • 5*x = 25 // : 5
  • x = 25/5
  • x = 5
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (7-(2*x))/3: 
  • y = (7-(2*5))/3
  • y = (7-10)/3
  • y = -3/3
  • y = -1
  • We get a system of equations:
  • /| y = -1| x = 5

 

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