2x+4(2+x)=7+3(x+1)

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Solution for 2x+4(2+x)=7+3(x+1) equation:



2x+4(2+x)=7+3(x+1)
We move all terms to the left:
2x+4(2+x)-(7+3(x+1))=0
We add all the numbers together, and all the variables
2x+4(x+2)-(7+3(x+1))=0
We multiply parentheses
2x+4x-(7+3(x+1))+8=0
We calculate terms in parentheses: -(7+3(x+1)), so:
7+3(x+1)
determiningTheFunctionDomain 3(x+1)+7
We multiply parentheses
3x+3+7
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
We add all the numbers together, and all the variables
6x-(3x+10)+8=0
We get rid of parentheses
6x-3x-10+8=0
We add all the numbers together, and all the variables
3x-2=0
We move all terms containing x to the left, all other terms to the right
3x=2
x=2/3
x=2/3

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