2x+4(3-2x)=(3(2x+2))/(6)+4

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Solution for 2x+4(3-2x)=(3(2x+2))/(6)+4 equation: 



2x+4(3-2x)=(3(2x+2))/(6)+4

We move all terms to the left:

2x+4(3-2x)-((3(2x+2))/(6)+4)=0

We add all the numbers together, and all the variables

2x+4(-2x+3)-((3(2x+2))/6+4)=0

We multiply parentheses

2x-8x-((3(2x+2))/6+4)+12=0

We multiply all the terms by the denominator


2x*6+4)-8x*6+4)-((3(2x+2))+12*6+4)=0

Wy multiply elements

12x+4)-8x*6+4)-((3(2x+2))+12*6+4)=0

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