2x+4(3-2x)=(3(2x+2))/6+4

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Solution for 2x+4(3-2x)=(3(2x+2))/6+4 equation:



2x+4(3-2x)=(3(2x+2))/6+4
We move all terms to the left:
2x+4(3-2x)-((3(2x+2))/6+4)=0
We add all the numbers together, and all the variables
2x+4(-2x+3)-((3(2x+2))/6+4)=0
We multiply parentheses
2x-8x-((3(2x+2))/6+4)+12=0
We multiply all the terms by the denominator
2x*6+4)-8x*6+4)-((3(2x+2))+12*6+4)=0
Wy multiply elements
12x+4)-8x*6+4)-((3(2x+2))+12*6+4)=0

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