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2x+4(3-2x)=3(2x+2)
We move all terms to the left:
2x+4(3-2x)-(3(2x+2))=0
We add all the numbers together, and all the variables
2x+4(-2x+3)-(3(2x+2))=0
We multiply parentheses
2x-8x-(3(2x+2))+12=0
We calculate terms in parentheses: -(3(2x+2)), so:We add all the numbers together, and all the variables
3(2x+2)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
-6x-(6x+6)+12=0
We get rid of parentheses
-6x-6x-6+12=0
We add all the numbers together, and all the variables
-12x+6=0
We move all terms containing x to the left, all other terms to the right
-12x=-6
x=-6/-12
x=1/2
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