2x+4(3-2x)=3(2x+2)6+4

Solution for 2x+4(3-2x)=3(2x+2)6+4 equation:

2x+4(3-2x)=3(2x+2)6+4

We move all terms to the left:

2x+4(3-2x)-(3(2x+2)6+4)=0

We add all the numbers together, and all the variables

2x+4(-2x+3)-(3(2x+2)6+4)=0

We multiply parentheses

2x-8x-(3(2x+2)6+4)+12=0


We calculate terms in parentheses: -(3(2x+2)6+4), so:

3(2x+2)6+4

We multiply parentheses

36x+36+4

We add all the numbers together, and all the variables

36x+40

Back to the equation:

-(36x+40)


We add all the numbers together, and all the variables

-6x-(36x+40)+12=0

We get rid of parentheses

-6x-36x-40+12=0

We add all the numbers together, and all the variables

-42x-28=0

We move all terms containing x to the left, all other terms to the right

-42x=28

x=28/-42

x=-2/3