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2x+4(3-2x)=3(2x+2/)6+4
We move all terms to the left:
2x+4(3-2x)-(3(2x+2/)6+4)=0
We add all the numbers together, and all the variables
2x+4(-2x+3)-(3(+2x+2/)6+4)=0
We multiply parentheses
2x-8x-(3(+2x+2/)6+4)+12=0
We multiply all the terms by the denominator
2x*)6+4)-8x*)6+4)-(3(+2x+2+12*)6+4)=0
We add all the numbers together, and all the variables
2x*)6+4)-8x*)6+4)-(3(+2x)6+4)=0
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