2x+4(3-2x)=3(x+10)

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Solution for 2x+4(3-2x)=3(x+10) equation: 



2x+4(3-2x)=3(x+10)

We move all terms to the left:

2x+4(3-2x)-(3(x+10))=0

We add all the numbers together, and all the variables

2x+4(-2x+3)-(3(x+10))=0

We multiply parentheses

2x-8x-(3(x+10))+12=0



We calculate terms in parentheses: -(3(x+10)), so:

3(x+10)

We multiply parentheses

3x+30

Back to the equation:

-(3x+30)



We add all the numbers together, and all the variables

-6x-(3x+30)+12=0

We get rid of parentheses

-6x-3x-30+12=0

We add all the numbers together, and all the variables

-9x-18=0

We move all terms containing x to the left, all other terms to the right

-9x=18

x=18/-9

x=-2

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