2x+4(3x-2)=18

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Solution for 2x+4(3x-2)=18 equation: 



2x+4(3x-2)=18

We move all terms to the left:

2x+4(3x-2)-(18)=0

We multiply parentheses

2x+12x-8-18=0

We add all the numbers together, and all the variables

14x-26=0

We move all terms containing x to the left, all other terms to the right

14x=26

x=26/14

x=1+6/7

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