2x+4(3x-6)=32

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Solution for 2x+4(3x-6)=32 equation: 



2x+4(3x-6)=32

We move all terms to the left:

2x+4(3x-6)-(32)=0

We multiply parentheses

2x+12x-24-32=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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