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2x+4(5x-3)=3x-4(5x+7)
We move all terms to the left:
2x+4(5x-3)-(3x-4(5x+7))=0
We multiply parentheses
2x+20x-(3x-4(5x+7))-12=0
We calculate terms in parentheses: -(3x-4(5x+7)), so:We add all the numbers together, and all the variables
3x-4(5x+7)
We multiply parentheses
3x-20x-28
We add all the numbers together, and all the variables
-17x-28
Back to the equation:
-(-17x-28)
22x-(-17x-28)-12=0
We get rid of parentheses
22x+17x+28-12=0
We add all the numbers together, and all the variables
39x+16=0
We move all terms containing x to the left, all other terms to the right
39x=-16
x=-16/39
x=-16/39
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