2x+4(5x-3)=3x-4(5x+7)

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Solution for 2x+4(5x-3)=3x-4(5x+7) equation: 



2x+4(5x-3)=3x-4(5x+7)

We move all terms to the left:

2x+4(5x-3)-(3x-4(5x+7))=0

We multiply parentheses

2x+20x-(3x-4(5x+7))-12=0



We calculate terms in parentheses: -(3x-4(5x+7)), so:

3x-4(5x+7)

We multiply parentheses

3x-20x-28

We add all the numbers together, and all the variables

-17x-28

Back to the equation:

-(-17x-28)



We add all the numbers together, and all the variables

22x-(-17x-28)-12=0

We get rid of parentheses

22x+17x+28-12=0

We add all the numbers together, and all the variables

39x+16=0

We move all terms containing x to the left, all other terms to the right

39x=-16

x=-16/39

x=-16/39

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