2x+4(x+1)=3(2x-1)+7

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Solution for 2x+4(x+1)=3(2x-1)+7 equation: 


Simplifying
2x + 4(x + 1) = 3(2x + -1) + 7

Reorder the terms:
2x + 4(1 + x) = 3(2x + -1) + 7
2x + (1 * 4 + x * 4) = 3(2x + -1) + 7
2x + (4 + 4x) = 3(2x + -1) + 7

Reorder the terms:
4 + 2x + 4x = 3(2x + -1) + 7

Combine like terms: 2x + 4x = 6x
4 + 6x = 3(2x + -1) + 7

Reorder the terms:
4 + 6x = 3(-1 + 2x) + 7
4 + 6x = (-1 * 3 + 2x * 3) + 7
4 + 6x = (-3 + 6x) + 7

Reorder the terms:
4 + 6x = -3 + 7 + 6x

Combine like terms: -3 + 7 = 4
4 + 6x = 4 + 6x

Add '-4' to each side of the equation.
4 + -4 + 6x = 4 + -4 + 6x

Combine like terms: 4 + -4 = 0
0 + 6x = 4 + -4 + 6x
6x = 4 + -4 + 6x

Combine like terms: 4 + -4 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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