2x+4(x+3)=7(2x-3)-3(2x-9)

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Solution for 2x+4(x+3)=7(2x-3)-3(2x-9) equation: 



2x+4(x+3)=7(2x-3)-3(2x-9)

We move all terms to the left:

2x+4(x+3)-(7(2x-3)-3(2x-9))=0

We multiply parentheses

2x+4x-(7(2x-3)-3(2x-9))+12=0



We calculate terms in parentheses: -(7(2x-3)-3(2x-9)), so:

7(2x-3)-3(2x-9)

We multiply parentheses

14x-6x-21+27

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

6x-(8x+6)+12=0

We get rid of parentheses

6x-8x-6+12=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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