2x+4(x-1)=3(-x+4)

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Solution for 2x+4(x-1)=3(-x+4) equation: 



2x+4(x-1)=3(-x+4)

We move all terms to the left:

2x+4(x-1)-(3(-x+4))=0

We add all the numbers together, and all the variables

2x+4(x-1)-(3(-1x+4))=0

We multiply parentheses

2x+4x-(3(-1x+4))-4=0



We calculate terms in parentheses: -(3(-1x+4)), so:

3(-1x+4)

We multiply parentheses

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

6x-(-3x+12)-4=0

We get rid of parentheses

6x+3x-12-4=0

We add all the numbers together, and all the variables

9x-16=0

We move all terms containing x to the left, all other terms to the right

9x=16

x=16/9

x=1+7/9

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