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2x+4(x-2)=3(2x-3)
We move all terms to the left:
2x+4(x-2)-(3(2x-3))=0
We multiply parentheses
2x+4x-(3(2x-3))-8=0
We calculate terms in parentheses: -(3(2x-3)), so:We add all the numbers together, and all the variables
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
6x-(6x-9)-8=0
We get rid of parentheses
6x-6x+9-8=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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