2x+4(x-3)+5=5(x-10)+x-2

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Solution for 2x+4(x-3)+5=5(x-10)+x-2 equation: 



2x+4(x-3)+5=5(x-10)+x-2

We move all terms to the left:

2x+4(x-3)+5-(5(x-10)+x-2)=0

We multiply parentheses

2x+4x-(5(x-10)+x-2)-12+5=0



We calculate terms in parentheses: -(5(x-10)+x-2), so:

5(x-10)+x-2

We add all the numbers together, and all the variables

x+5(x-10)-2

We multiply parentheses

x+5x-50-2

We add all the numbers together, and all the variables

6x-52

Back to the equation:

-(6x-52)



We add all the numbers together, and all the variables

6x-(6x-52)-7=0

We get rid of parentheses

6x-6x+52-7=0

We add all the numbers together, and all the variables

45!=0

There is no solution for this equation

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