2x+4(x-5)+12=-20

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Solution for 2x+4(x-5)+12=-20 equation: 



2x+4(x-5)+12=-20

We move all terms to the left:

2x+4(x-5)+12-(-20)=0

We add all the numbers together, and all the variables

2x+4(x-5)+32=0

We multiply parentheses

2x+4x-20+32=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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