2x+4(x-7)=2(x-8)

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Solution for 2x+4(x-7)=2(x-8) equation: 



2x+4(x-7)=2(x-8)

We move all terms to the left:

2x+4(x-7)-(2(x-8))=0

We multiply parentheses

2x+4x-(2(x-8))-28=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

6x-(2x-16)-28=0

We get rid of parentheses

6x-2x+16-28=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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