2x+4(x-8)=-3(x-2)+7

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Solution for 2x+4(x-8)=-3(x-2)+7 equation: 



2x+4(x-8)=-3(x-2)+7

We move all terms to the left:

2x+4(x-8)-(-3(x-2)+7)=0

We multiply parentheses

2x+4x-(-3(x-2)+7)-32=0



We calculate terms in parentheses: -(-3(x-2)+7), so:

-3(x-2)+7

We multiply parentheses

-3x+6+7

We add all the numbers together, and all the variables

-3x+13

Back to the equation:

-(-3x+13)



We add all the numbers together, and all the variables

6x-(-3x+13)-32=0

We get rid of parentheses

6x+3x-13-32=0

We add all the numbers together, and all the variables

9x-45=0

We move all terms containing x to the left, all other terms to the right

9x=45

x=45/9

x=5

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