2x+4(x-8)=7x+3(x-10)

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Solution for 2x+4(x-8)=7x+3(x-10) equation: 



2x+4(x-8)=7x+3(x-10)

We move all terms to the left:

2x+4(x-8)-(7x+3(x-10))=0

We multiply parentheses

2x+4x-(7x+3(x-10))-32=0



We calculate terms in parentheses: -(7x+3(x-10)), so:

7x+3(x-10)

We multiply parentheses

7x+3x-30

We add all the numbers together, and all the variables

10x-30

Back to the equation:

-(10x-30)



We add all the numbers together, and all the variables

6x-(10x-30)-32=0

We get rid of parentheses

6x-10x+30-32=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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