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2x+4+8x+12=3x+6+3x+22
We move all terms to the left:
2x+4+8x+12-(3x+6+3x+22)=0
We add all the numbers together, and all the variables
2x+8x-(6x+28)+4+12=0
We add all the numbers together, and all the variables
10x-(6x+28)+16=0
We get rid of parentheses
10x-6x-28+16=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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