2x+4-2(2x-2)=3(x-4)

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Solution for 2x+4-2(2x-2)=3(x-4) equation: 



2x+4-2(2x-2)=3(x-4)

We move all terms to the left:

2x+4-2(2x-2)-(3(x-4))=0

We multiply parentheses

2x-4x-(3(x-4))+4+4=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

-2x-(3x-12)+8=0

We get rid of parentheses

-2x-3x+12+8=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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