2x+4-2(x+3)=10

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Solution for 2x+4-2(x+3)=10 equation: 



2x+4-2(x+3)=10

We move all terms to the left:

2x+4-2(x+3)-(10)=0

We add all the numbers together, and all the variables

2x-2(x+3)-6=0

We multiply parentheses

2x-2x-6-6=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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