2x+4-5(x+2)=1/3(3x-21)+1

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Solution for 2x+4-5(x+2)=1/3(3x-21)+1 equation: 



2x+4-5(x+2)=1/3(3x-21)+1

We move all terms to the left:

2x+4-5(x+2)-(1/3(3x-21)+1)=0



Domain of the equation: 3(3x-21)+1)!=0

x∈R



We multiply parentheses

2x-5x-(1/3(3x-21)+1)-10+4=0

We multiply all the terms by the denominator


2x*3(3x-21)+1)-5x*3(3x-21)+1)-(1-10*3(3x-21)+1)+4*3(3x-21)+1)=0

Wy multiply elements

6x^2(3+1)-5x*3(3x-21)-10*3(3x-21)+1)+4*3(3x+1)-(1-21)+1)=0

We add all the numbers together, and all the variables

6x^24-5x*3(3x-21)-10*3(3x-21)+1)+4*3(3x+1)-(-20)+1)=0

We add all the numbers together, and all the variables

6x^24-5x*3(3x-21)-10*3(3x-21)+1)+4*3(3x=0

Wy multiply elements

6x^24-15x^2(3-30x(3+1)+4*3(3x=0

We do not support expression: x^24

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