2x+4-5(x-2)=1/3(3x-21)+1

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Solution for 2x+4-5(x-2)=1/3(3x-21)+1 equation:



2x+4-5(x-2)=1/3(3x-21)+1
We move all terms to the left:
2x+4-5(x-2)-(1/3(3x-21)+1)=0
Domain of the equation: 3(3x-21)+1)!=0
x∈R
We multiply parentheses
2x-5x-(1/3(3x-21)+1)+10+4=0
We multiply all the terms by the denominator
2x*3(3x-21)+1)-5x*3(3x-21)+1)-(1+10*3(3x-21)+1)+4*3(3x-21)+1)=0
Wy multiply elements
6x^2(3+1)-5x*3(3x-21)+10*3(3x-21)+1)+4*3(3x+1)-(1-21)+1)=0
We add all the numbers together, and all the variables
6x^24-5x*3(3x-21)+10*3(3x-21)+1)+4*3(3x+1)-(-20)+1)=0
We add all the numbers together, and all the variables
6x^24-5x*3(3x-21)+10*3(3x-21)+1)+4*3(3x=0
Wy multiply elements
6x^24-15x^2(3+30x(3+1)+4*3(3x=0
We do not support expression: x^24

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