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2x+4-5x(x=5)
We move all terms to the left:
2x+4-5x(x-(5))=0
We multiply parentheses
-5x^2+2x+25x+4=0
We add all the numbers together, and all the variables
-5x^2+27x+4=0
a = -5; b = 27; c = +4;
Δ = b2-4ac
Δ = 272-4·(-5)·4
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{809}}{2*-5}=\frac{-27-\sqrt{809}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{809}}{2*-5}=\frac{-27+\sqrt{809}}{-10} $
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